If a transparent medium of refractive index `mu=1.5` and thickness `t=2.5xx10^-5m` is inserted in front of one of the slits of Young's Double Slit experiment, how much will be the shift in the interference patten? The distance between the slits is `0.5mm` and that between slits and screen is `100cm`

Options

A. `5 cm`
B. `2.5 cm`
C. `0.25 cm`
D. `0.1 cm`

Answer

B

Explanation

Shift in interference pattern
`y_(0)=(mu-1)tD/d`
`=(3/2-1)xx2.5xx10^(-5)xx1/(0.5xx10^(-3))`
`=2.5xx10^(-2)m=2.5 cm`