Equation of normal of ellipse

Find the equation of normal to the ellipse x^(2)+4y^(2)=4 at (2cos theta,sin theta). Hence,find the equation of normal to this ellipse which is parallel to the line 8x+3y=0.

The equation of normal to the ellipse 4x^(2)+9y^(2)=72 at point (3,2) is:

The equation of normal to the ellipse x^(2)+4y^(2)=9 at the point wherr ithe eccentric angle is pi//4 is

The ellipse x^2/a^2+y^2/b^2=1,(a gt b) passes through (2,3) and have eccentricity equal to 1/2 . Then find the equation of normal to the ellipse at (2,3) .

Let S(x_(1),0) for x_(1)>0 is focus of the ellipse E:(x^(2))/(9)+(y^(2))/(4)=1. Suppose a parabola whose vertex is V(x_(1)sqrt(5),0) touches the ellipse at points A and B in I and IV quadrants respectively. Axis of parabola is x - axis. Equation of normal to the ellipse E at A is

Normal To Ellipse

Equation of normal of rectangular hyperbola

Equation of a normal to the given ellipse whose slope is 'm' is y=ma-+((a^(2)-b^(2))m)/(sqrt(a^(2)+b^(2)m^(2)))

Find the equation of the ellipse