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If a body covers first half of its journ...

If a body covers first half of its journey with uniform speed `v_(1)` and the second half of the journey with uniform speed `v_(2)`. Then the average speed is

A

`V_(1)+V_(2)`

B

`(2V_(1)V_(2))/(V_(1)+V_(2))`

C

`(V_(1)V_(2))/(V_(1)+V_(2))`

D

`V_(1)V_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the average speed of a body that covers the first half of its journey with uniform speed \( v_1 \) and the second half with uniform speed \( v_2 \), we can follow these steps: ### Step-by-Step Solution: 1. **Define the Total Distance**: Let the total distance of the journey be \( S \). Therefore, the first half of the journey is \( \frac{S}{2} \) and the second half is also \( \frac{S}{2} \). 2. **Calculate Time for Each Half**: - For the first half of the journey (distance \( \frac{S}{2} \) at speed \( v_1 \)): \[ T_1 = \frac{\text{Distance}}{\text{Speed}} = \frac{\frac{S}{2}}{v_1} = \frac{S}{2v_1} \] - For the second half of the journey (distance \( \frac{S}{2} \) at speed \( v_2 \)): \[ T_2 = \frac{\text{Distance}}{\text{Speed}} = \frac{\frac{S}{2}}{v_2} = \frac{S}{2v_2} \] 3. **Calculate Total Time**: The total time \( T \) taken for the journey is the sum of \( T_1 \) and \( T_2 \): \[ T = T_1 + T_2 = \frac{S}{2v_1} + \frac{S}{2v_2} \] To simplify this, we can factor out \( \frac{S}{2} \): \[ T = \frac{S}{2} \left( \frac{1}{v_1} + \frac{1}{v_2} \right) \] 4. **Calculate Average Speed**: The average speed \( V_{\text{avg}} \) is defined as the total distance divided by the total time: \[ V_{\text{avg}} = \frac{\text{Total Distance}}{\text{Total Time}} = \frac{S}{T} \] Substituting the expression for \( T \): \[ V_{\text{avg}} = \frac{S}{\frac{S}{2} \left( \frac{1}{v_1} + \frac{1}{v_2} \right)} \] Simplifying this gives: \[ V_{\text{avg}} = \frac{S \cdot 2}{S \left( \frac{1}{v_1} + \frac{1}{v_2} \right)} = \frac{2}{\left( \frac{1}{v_1} + \frac{1}{v_2} \right)} \] 5. **Final Expression**: The expression can be rewritten using the formula for the harmonic mean: \[ V_{\text{avg}} = \frac{2v_1v_2}{v_1 + v_2} \] ### Conclusion: Thus, the average speed of the body for the entire journey is: \[ V_{\text{avg}} = \frac{2v_1v_2}{v_1 + v_2} \]

To find the average speed of a body that covers the first half of its journey with uniform speed \( v_1 \) and the second half with uniform speed \( v_2 \), we can follow these steps: ### Step-by-Step Solution: 1. **Define the Total Distance**: Let the total distance of the journey be \( S \). Therefore, the first half of the journey is \( \frac{S}{2} \) and the second half is also \( \frac{S}{2} \). 2. **Calculate Time for Each Half**: ...
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