A body is thrown vertically up to reach its maximum height in t seconds. The total time from the time of projection to reach a point at half of its maximum height while returning (in seconds) is

Options

A. `sqrt(2)t`
B. `(1+(1)/(sqrt(2)))t`
C. `(3t)/(2)`
D. `(t)/(sqrt(2))`

Answer

B

Explanation

`H=(1)/(2)"gt"^(2) ,(H)/(2)=(1)/(2) (t')^(2) , "find" t'=?`
Total time `= t + t'`