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A ball is released from the top of a tow...

A ball is released from the top of a tower of height `H m`. After `2 s` is stopped and then instantaneously released. What will be its height after next `2 s`?.

A

`H-5`

B

`H-10`

C

`H-20`

D

`H-40`

Text Solution

Verified by Experts

The correct Answer is:
D

`h_(1)=(1)/(2)g t_(1)^(2)(t=2sec),h_(2)=(1)/(2)g t_(2)^(2)(t=2sec)`
`h'=H-(h_(1)+h_(2))`
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