A parachutist after bailing out falls for 10 s without friction. When the parachute opens he descends with an acceleration of `2 m//s^(2)` against his direction and reached the ground with `4 m//s` from what height he has dropped himself? `(g=10 m//s^(2))`

Options

A. `500m`
B. `2496m`
C. `2996m`
D. `4296m`

Answer

C

Explanation

`S_(1)=(1)/(2)g t^(2),v=g t , v_(1)^(2)-v^(2)=2as_(2),S=S_(1)+S_(2)`