The displacement of a particle is moving by `x = (t - 2)^2` where `x` is in metres and `t` in second. The distance covered by the particle in first `4` seconds is.

Options

A. 4m
B. 8m
C. 12 m
D. 16 m

Answer

B

Explanation

Given `x=(t-2)^(2)`
velocity, `v=(dx)/(dt)=(d)/(dt)(t-2)^(2)=2(t-2)m//s`
Acceleration `a=(dv)/(dt)=(d)/(dt)[2(t-2)]`
`=2[1-0]=2 m//s^(2)`