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A body is moving with uniform velocity of `8 ms^-1`. When the body just crossed another body, the second one starts and moves with uniform acceleration of `4 ms^-2`. The time after which two bodies meet will be :

A

2s

B

4s

C

6s

D

8s

Text Solution

Verified by Experts

The correct Answer is:
B
Let they meet after time t, then the distance travelled by both in time t should be same
`s=8t=(1)/(2)4t^(2)impliest=4s`
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