A particle starts sliding down a frictionless inclined plane. If ` S_(n) ` is the distance travelled by it from time ` t = n-1 sec `, to `t = n sec`, the ratio ` (S_(n))/(s_(n+1))` is

Options

A. `(2n-1)/(2n)`
B. `(2n+1)/(2n-1)`
C. `(2n-1)/(2n+1)`
D. `(2n)/(2n+1)`

Answer

C

Explanation

Distance traveled in `t^(th)` second is
`s_(t)=u+at-(1)/(2)a` given : `u=0`
`:. (s_(n))/(s_(n+1))=(an-(1)/(2)a)/(a(n+1)-(1)/(2)a)=(2n-1)/(2n+1)`
Hence, the correct option is (C).