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Two stones are thrown up simultaneously with initial speeds of `u_(1)` and `u_(2)(u_(2)gt_(1) u_(1))`. They hit the ground after 6 s and 10 s respectively. Which graph in fig. correctly represents the time variation of `Deltax=(x_(2)-x_(1))` the relative position of the second stone with respect to the first upto `t=10` s? Assume that the stones do not rebound after hitting the ground.

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
A
`x_(1)=u_(1)t-(1)/(2)g t^(2)`
`x_(2)=u_(2)t-(1)/(2)g t^(2)`
in is valid up `t=6` sec only
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