[" (i) "(1)/(sqrt(7))" (ii) "(sqrt(5))/(2sqrt(3))quad " (ii) "(1)/(2+sqrt(3))],[" (v) "(1)/(sqrt(5)-2)quad " (v) "(1)/(5+3sqrt(2))quad " (vi) "(1)/(sqrt(7)-sqrt(6))],[[" 4"," (vii) "(1+sqrt(2))/(2-sqrt(2))" pout the following "],[sqrt(11)-sqrt(7)," Roich "]]

Rationalise the denominator of each of the following. (i) (1)/(sqrt(7)) (ii) (sqrt(5))/(2sqrt(3)) (iii) (1)/(2+ sqrt(3)) (1)/(sqrt(3)) (v) (1)/((5+3sqrt(2)) (vi) (1)/(sqrt(7) - sqrt(6)) (vi) (1)/(sqrt(7) - sqrt(6)) (viii) (1+ sqrt(2))/(2-sqrt(2)) (ix) (3-2sqrt(2))/(3+2sqrt(2))

(1)/(sqrt(2)+sqrt(5)-sqrt(7))

(1)/(sqrt(7)-sqrt(2))-(1)/(sqrt(7)+sqrt(2))=

Simplify: (7+3sqrt(5))/(3+sqrt(5))-(7-3sqrt(5))/(3-sqrt(5)) (ii) (1)/(2+sqrt(3))+(2)/(sqrt(5)-sqrt(3))+(1)/(2-sqrt(5))

(1)/(3-sqrt(8))-(1)/(sqrt(8)-sqrt(7))+(1)/(sqrt(7)-sqrt(6))-(1)/(sqrt(6)-sqrt(5))+(1)/(sqrt(5)-2)=5

(1)/(3-sqrt(8))-(1)/(sqrt(8)-sqrt(7))+(1)/(sqrt(7))-sqrt(6))-(1)/(sqrt(6)-sqrt(5))+(1)/(sqrt(5)-2)=5

(1)/(3-sqrt(8))-(1)/(sqrt(8)-sqrt(7))+(1)/(sqrt(7)-sqrt(6))-(1)/(sqrt(6)-sqrt(5))+(1)/(sqrt(5)-2)=5

The value of (1)/( sqrt(7) - sqrt(6)) - (1)/( sqrt(6) - sqrt(5) ) +(1)/( sqrt(5) -2) - (1)/( sqrt(8) - sqrt(7) ) +(1)/( 3- sqrt(8)) is

(1)/(2sqrt(7)+sqrt(5))-(1)/(2sqrt(5)+sqrt(7)) simplify