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A particle is thrown in vertically in up...

A particle is thrown in vertically in upward direction and passes three equally spaced windows of equal heights. Then

A

Average speed of the particle while passing the windows satisfies the relation `u_(av_(1))gtu_(av_(2))gtu_(av_(3))`

B

the time taken by the particle to cross the windows satisfies the relation `t_(1)gtt_(2)gt_t_(3)`

C

The magnitude of the acceleration of the particle while crossing the windows satisfies the relation `a_(1)=a_(2)nea_(3)`

D

the charge in the speed of the particle while crossing the windows would satisfy the relation `Deltau_(1)ltDeltau_(2)ltDeltau_(3)`

Text Solution

Verified by Experts

The correct Answer is:
A, B, D
As the particle is going up, it is slowing down i.e., speed is decreasing and hence we can say that time taken by the particle to cover equal distances is increasing as the particle is going up.
Hence `t_(1)ltt_(2)ltt_(3)`.
As `u_(av)=("distance")/("time")`, we have `u_(av)prop(1)/("time")`
Acceleration throughout the motion remains same from equation,
`vecv=vec(u)+vec(at), Deltaupropt` So, `Deltau_(1)ltDeltau_(2)ltDeltau_(3)`
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