`vecP,vecQ,vecR,vecS` are vector of equal magnitude. If `vecP+vecQ-vecR=0` angle between `vecP` and `vecQ` is `theta_(1)`.If `vecP+vecQ-vecS=0` angle between `vecP` and `vecS` is `theta_(2)`.The ratio of `theta_(1)` to`theta_(2)` is

Options

A. `1:2`
B. `2:1`
C. `1:1`
D. `1:sqrt3`

Answer

B

Explanation

`vecP+vecQ=vecR,vecP+vecQ=vecS`,
`theta_(2)= "tan"^(-1)(Qsintheta_(1))/(P+Qcostheta_(1)),theta_(1)/theta_(2)=?`