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Three forces vecA=(hati+hatj+hatk),vecB=...

Three forces `vecA=(hati+hatj+hatk),vecB=(2hati-hatj+3hatk)` and `vecC` acting on a body to keep it in equilibrium. Then `vecC` is

A

`-(3hati+4hatk)`

B

`-(4hati+3hatk)`

C

`(3hati+4hatj)`

D

`(2hati-3hatk)`

Text Solution

Verified by Experts

The correct Answer is:
A
`vecA+vecB+vecC=0,vecC=-(vecA+vecB)`
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