An aeroplane is flying horizontally at a height of `980 m` with velocity `100 ms^(-1)` drops a food packet.A person on the ground is `414 m` ahead horizontally from the dropping point.At what velocity should he move so that he can catch the food packet.

Options

A. `50sqrt2ms^(-1)`
B. `50/sqrt2ms^(-1)`
C. `100ms^(-1)`
D. `200ms^(-1)`

Answer

A

Explanation

`T=sqrt((2h)/g),R=usqrt((2h)/g)`
Remaining distance`=(R-414),v=R-414/T`