A cylclist is riding with a speed of `27 km h^-1`. As he approaches a circular turn on the road of radius `80 m`, he applies brakes and reduces his speed at the constant rate of `0.5 ms^-2`. What is the magnitude and direction of the net acceleration of the cyclist on the circular turn ?

Options

A. `0.5m//s^(2)`
B. `0.87m//s^(2)`
C. `0.56m//s^(2)`
D. `1m//s^(2)`

Answer

C

Explanation

`a=sqrt(a_(c)^(2)+a_(r)^(2))`