A ball is thrown from a point with a speed `V_(0)`,at an angle of projection `theta`.From the same point and at the same instance a person starts running with a constant speed `V_(0)/sqrt2` to catch the ball will the person be able to catch the ball? If yes, what should be the angle of projection

Options

A. yes, `60^(@)`
B. yes, `30^(@)`
C. No
D. yes, `45^(@)`

Answer

D

Explanation

`R=(V_(0)^(2)sin 2theta)/g` and `T=(2V_(0)sin theta)/g`fro projectile `S=Vt` for the person For angle, equate range of the projectile with the distance travelled by the person.