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The coach throws a baseball to a player ...

The coach throws a baseball to a player with an initial speed at `20ms^(-1)` at an angle of `45^(@)` with the horizontal.At the moment the ball is thrown, the player is `50m` from coach.The speed and the direction that the player has to run to catch the ball at the same height at which it was released in `ms^(-1)` is

A

`5/sqrt2`away from coach

B

`5/sqrt2` towards from coach

C

`sqrt2/5`towards the coach

D

`sqrt2/5`away from the coach

Text Solution

Verified by Experts

The correct Answer is:
B
`R_("ball")=(u^(2)sin2theta)/g,s=vt`
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