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A ball is projected from the top of a to...

A ball is projected from the top of a tower with a velocity `3hati+4hatj+5hatk ms^(-1)`,where `hati+hatj+hatk` are unit vectors along east, north and vertical upwards respectively. If the height of the tower is `30 m`, its range is `(g=10 ms^(-1))`

A

`12 m`

B

`9 m`

C

`15 m`

D

`25 m`

Text Solution

Verified by Experts

The correct Answer is:
C
`T=(u sin theta+sqrt((u sin theta)^(2)+2gH))/g,R=u cos theta.T`
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Knowledge Check

  • A ball is projected from the top of a tower with a velocity 3hati+4hatj+5hatk ms^(-1) ,where hati+hatj+hatk are unit vectors along east, north and vertical upwards respectively. If the height of the tower is 30 m , its time is (g=10ms^(-1))

    A
    5
    B
    3
    C
    0.3
    D
    0.5

  • The vector component of vector vecA =3hati +4hatj +5hatk along vector vecB =hati +hatj +hatk is :

    A
    `2hati +2hatj+2hatk`
    B
    `3hati +3hatj +3hatk`
    C
    `4hati + 4hatj+4hatk`
    D
    `5hati +5hatj+5hatk`

  • A body is projected from the ground with a velocity v = (3hati +10 hatj)ms^(-1) . The maximum height attained and the range of the body respectively are (given g = 10 ms^(-2))

    A
    5 m and 6m
    B
    3m and 10m
    C
    6m and 5m
    D
    3m and 5m

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