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The direction of a projectile at a certa...

The direction of a projectile at a certain instant is inclined at an angle `prop` to the horizontal , after `t` second, it is inclined at an angle `beta`. Prove that the horizontal component of the velocity of the projectile is `("gt")/(tan prop - tan beta)`.

A

`g/(tan alpha-tan beta)`

B

`(g t)/(tan alpha-tan beta)`

C

`t/((tan alpha-tan beta))`

D

`(g t)/(tan alpha+tan beta)`

Text Solution

Verified by Experts

The correct Answer is:
B
`Tanalpha=V_(y)/(ucosalpha),Tanbeta=(V_(y)-"gt")/(ucosbeta)`
`Tanalpha-Tanbeta="gt"/(ucosbeta)`
`ucosbeta=ucosalpharArrucosbeta="gt"/(Tanalpha-Tanbeta)`
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