A particle moves in a circular path such that its speed `v` varies with distance `s` as `v = prop sqrt(s)` , where `prop` is a positive constant. Find the acceleration of the particle after traversing a distance `s`.

Options

A. `alpha^(2)sqrt(1/4-S^(2)/R^(2)`
B. `alpha^(2)sqrt(1/4+S^(2)/R^(2)`
C. `alphasqrt(1/4+S^(2)/R^(2)`
D. `alpha^(2)sqrt(1/4+S^(2)/R^(2)`

Answer

B

Explanation

`a=sqrt(a_(t)^(2)+a_(t)^(2))=sqrt(((dv)/(dt))^(2)+((v^(2))/(R))^(2)`