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A cricket fielder can throw the cricket ...

A cricket fielder can throw the cricket ball with a speed `v_(0)`.If the throws the ball while running with speed `u` at an angle `theta` to the horizontal.
The effective angle to the horizontal at which the ball is projected in air as seen by a spector is

A

`theta=tan^(-1)((v_(0)sin theta)/(u+v_(0) cos theta))`

B

`theta=tan^(-1)((v_(0)cos theta)/(u+v_(0) sin theta))`

C

`theta=cot^(-1)((v_(0)cos theta)/(u+v_(0) sin theta))`

D

`theta=cot^(-1)((v_(0)cos theta)/(u+v_(0) sin theta))`

Text Solution

Verified by Experts

The correct Answer is:
A
`u_(x)=u+v_(0)cos theta`
`u_(y) =` inital velocity in y-direction
`v_(0)=sin theta`
`tan theta=u_(y)/u_(x)`
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