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Given that vecA+vecB+vecC=0, out of thre...

Given that `vecA+vecB+vecC=0`, out of three vectors two are equal in magnitude and the magnitude of third vector is `sqrt2` times that of either of two having equal magnitude. Then angle between vectors are given by

A

`30^(@),60^(@),90^(@)`

B

`45^(@),135^(@),150^(@)`

C

`90^(@),135^(@),150^(@)`

D

`90^(@),135^(@),135^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D
`vecA+vecB=vecC.|vecA|=|vecB|,sqrt2|A|=vecC`
angle between `vecA` and `vecB` is `90^(@)`
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