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Two particles having position vectors ve...

Two particles having position vectors `vecr_(1)=(3veci+5 vecj)m` and `vecr_(2)=(-5veci+3 vecj)m` are moving with velocities `vecV_(1)=(4hati-4hatj)ms^(-1)` and `vecV_(2)=(1hati-3hatj)ms^(-1)`. If they collide after `2 ` seconds, the value of `a` is

A

`2`

B

`4`

C

`6`

D

`8`

Text Solution

Verified by Experts

The correct Answer is:
C
`vecr_(1)+vecv_(1)t=vecr_(2)+vecv_(2)t`
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