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The position of a particle is given by v...

The position of a particle is given by `vecr=3tveci-2t^(2)hatj+4hatk m` where `t` is in second and the co-efficients have proper units for `r` to be in `m`.The magnitude and direction of velocity of the particle at `t=2 s` is

A

`8.54 ms^(-1),20^(@)` with `x`-axis

B

`10.54 ms^(-1),70^(@)` with `x`-axis

C

`8.54 ms^(-1),70^(@)` with `x`-axis

D

`10.54 ms^(-1),20^(@)` with `x`-axis

Text Solution

Verified by Experts

The correct Answer is:
C
`vecv=((dvecr)/(dt))_(t=2s)`
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