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A particle starts from origin at `t=0` with a constant velocity `5hati m//s` and moves in `x-y` plane under action of a force which produce a constant acceleration of `(3hati+2hatj)m//s^(2)` the `y`-coordinate of the particle at the instant its `x` co-ordinate is `84 m` in `m` is

A

`6`

B

`36`

C

`18`

D

`9`

Text Solution

Verified by Experts

The correct Answer is:
B
`vecr=ut+1/2at^(2)`
equate `x` coordinate to `84` to find time `t`
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