A particle is moving along a circular path in `xy`-plane.When its crosses `x`-axis,it has an acceleration along the path of `1.5m//s^(2)`, and is moving with a speed of `10 m//s` in `-ve` `y`-direction.The total acceleration is

Options

A. `50hati-105 hatjm//s^(2)`
B. `10hati-1.5 hatjm//s^(2)`
C. `-50hati-1.5 hatjm//s^(2)`
D. `1.5hati-50 hatjm//s^(2)`

Answer

C

Explanation

`a=a_(r)(-hati)+a_(t)(-hatj)`