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If sin^(-1)x = y, then (A) 0lt=ylt=pi (B...

If `sin^(-1)x = y`, then (A) `0lt=ylt=pi` (B) `-pi/2lt=ylt=pi/2`(C) `0ltyltpi` (d) `-pi/ 2ltyltpi/ 2`

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To solve the problem, we need to analyze the function \( \sin^{-1}(x) \) (also known as arcsine) and determine the range of values for \( y \) when \( \sin^{-1}(x) = y \). ### Step-by-Step Solution: 1. **Understanding the Function**: The function \( \sin^{-1}(x) \) is defined for \( x \) in the interval \([-1, 1]\). This means that the input \( x \) must be within this range for the function to yield a real output. 2. **Finding the Range of \( y \)**: ...
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