Value of determinant formed by cofactors

If the value of a third order determinant is 11 then the value of the square of the determinant formed by the cofactors will be

If D is determinant of order three of Delta is a determinant formed by the cofactors of determinant D: then

Let Delta_0 = |(a_11, a_12, a_13), (a_21, a_22, a_23), (a_31, a_32, a_33)|, (where Delta_0 !=0) and let Delta_1 denote the determinant formed by the cofactors of elements of Delta_0 and Delta_2 denote the determinant formed by the cofactors at Delta_1 and so on Delta_n denotes the determinant formed by the cofactors at Delta_(n-1) then the determinant value of Delta_n is (A) (Delta_0)^(2n) (B) (Delta_0)^(2^n) (C) (Delta_0)^2 (D) (Delta_0)^(n^2)

Consider the determinants Delta=|{:(2,-1,3),(1,1,1),(1,-1,1):}|,Delta'=|{:(2,0,-2),(-2,-1,1),(-4,1,3):}| STATEMENT-1 Delta'=Delta^2 . STATEMENT-2 : The determinant formed by the cofactors of the elements of a determinant of order 3 is equal in value to the square of the original determinant.

If the value of a third order determinant is 11, find the value of the square of the determinat formed by the cofactors.

Circulant: Let a; b; c be positive and not all equal.Then the value of determinant formed by a; b and c in their circular form is negative.

If a, b and c are distinct and D = |(a,b,c),(b,c,a),(c,a,b)|. then the square of the determinant of its cofactors is divisible by