int0 ^(pi/2) log sinx dx = int0 ^(pi/2) ...

`int_0 ^(pi/2) log sinx dx = int_0 ^(pi/2) log cosx dx = 1/2 (pi) log(1/2)`

Text Solution

AI Generated Solution

Promotional Banner

Promotional Banner

Similar Questions

Explore conceptually related problems

int_(0)^(pi) x log sinx\ dx

Prove that: int_(0)^(pi//2) log (sin x) dx =int_(0)^(pi//2) log (cos x) dx =(-pi)/(2) log 2

int_(0)^(pi)log sin^(2)x dx=

int_(0)^(pi//2) log (cotx ) dx=

Prove that int_(0)^(pi//2)log (sinx)dx=int_(0)^(pi//2) log (cosx)dx=-(pi)/(2) log 2 .

int_0^(pi//2)log(tanx)dx

Prove that: int_0^(pi//2)logsinx\ dx=\ int_0^(pi//2)logcosx\ dx=-pi/2log2

int_(0)^(pi//2)log (sec x) dx=

int_(0)^(pi//2) log (tan x ) dx=

Recommended Questions

int0 ^(pi/2) log sinx dx = int0 ^(pi/2) log cosx dx = 1/2 (pi) log(1/2...
Text Solution
|
Evaluate: int0^pi log(1+cosx)dx
Text Solution
|
सिद्ध कीजिये - int(0)^(pi//2)log(sinx)dx=int(0)^(pi//2)log(cosx)dx=(...
Text Solution
|
int(0)^((pi)/(2))log(sinx)dx=int(0)^((pi)/(2))log(cosx)dx=(pi)/(2)log....
Text Solution
|
প্রমান করো int0^frac{pi}{2} (cosx dx)/{(1+sinx)(2+sinx)(3+sinx)}=frac{...
Text Solution
|
দেখাও যে, int0^(pi/2)[2log(sinx)-log(sin2x)]dx=pi/2(log)1/2
Text Solution
|
প্রমান করো: int0^(pi/2)log(sinx)dx=int0^(pi/2)log(cosx)dx
Text Solution
|
int0^(pi//2) log(tan x) dx is :
Text Solution
|
int0^(pi//2) log(tan x)dx =
Text Solution
|