Area of triangle by using integration

Sketch the region {(x, 0):y=sqrt(4-x^(2))} and X-axis. Find the area of the region using integration.

Sketch the region {(x, 0):y=sqrt(4-x^(2))} and X-axis. Find the area of the region using integration.

What is the minimum area of a triangle with integral vertices ?

If the vertices of a triangle having integral coordinates.Prove that triangle can't be equileteral.

Using integration,find the area of the triangle formed by negative x -axis and tangent and normal to the circle x^(2)+y^(2)=9 at (-1,2sqrt(2))

Sketch the region {(x,y): 4x ^(2) + 9y ^(2) = 36} and find its area, using integration.

The area of triangle formed by tangent at (1,1) on y=x^(2) +bx +c with coordinate axis is equal to 1 then the integral value of b is

Find the area of the circle x^2+y^2=16 which is exterior to the parabola y^2=6x by using integration.

If each of the vertices of a triangle has integral coordinates, then the triangles may be

Find the area common to two parabolas x^(2)=4ay and y^(2)=4ax, using integration.