fig. shows variation of stopping potential `(V_0)` with frequency (v) for two photosenstive matrials `M_1 and M_2`.

(i) why is the slope same for both lines?
(ii) For which material will the emitted electrons have greater kinetic energy for the incident radiations of the same frequency? Justify your answer.

Fig. shows the variation of stopping potential V_0 with the frequency v of the incident radiation for two photosenstive metal P and Q: (i) Explain which metal has smaller threshold wavelength (ii) Explain, giving reason, which metal emits photoelectrons having smaller kinetic energy, for the same wavelength of incident radiation. (iii) If the distance between the light source and metal P is doubled, how will the stopping potential change.

Fig. shows the variation of stopping potential V_0 with the frequency v of the incident radiation for two photosensitive metal P and Q: (i) Explain which metal has smaller threshold wavelength (ii) Explain, giving reason, which metal emits photoelectrons having smaller kinetic energy, for the same wavelength of incident radiation. (iii) If the distance between the light source and metal P is doubled, how will the stopping potential change.

The following graph shows the variation of stopping potential V_0 with the frequency v of the incident radiation for two photosensitive metals X and Y. (i) Which metal has larger threshold wavelength ? Give reason. (ii) Explain giving reason , which metal gives out electrons , having larger kinetic energy , for same wavelength of the incident radiation. (iii) If the distance between the light source and metal X is halved , how will the kinetic energy of electrons emitted from it change ? Given reason.

The graph shows variation of stopping potential V_(0) versus frequency of incident radiation v for two photosensitive metals A and B . Which of two metals has higher threshold frequency and why?

The graph shows variation of stopping potential V_(0) versus frequency of incident radiation v for two photosensitive metals A and B . Which of two metals has higher threshold frequency and why?

Figure show the variation of the stopping potential (V_(0)) with the frequency (v) of the incident radiations for two different photosensitive matererial M_(1) and M_(2) What are the values of work functions for M_(1) and M_(2) respectively

The figure shows the variation of stopping potential V_(Q) with the frequency v of the incident radiations for two photosensitive metals P and Which metal has smaller threshold wavelength ? Justify your answer.

Ultraviolet light is incident on two photosenstive materials having work functions phi_1 and phi_2 (phi_1 gt phi_2) . In which case will the K.E. of the emitted electrons be greater ? Why ?