If `veca` and `vecb` are the position vectors of A and B respectively; find the position vector of a point C on BA produced such that BC = 3/2 BA.
`veca = hati+hat j+hatk`
`vecb = 2hati-4hat j-9hatk`

Find vecA xx vecB if vecA = hati - 2hatj + 4hatk and vecB = 2hati - hatj + 2hatk

Find the sum of the vectors veca = -2hati+hatj-4hatk and vecb = 3hati-hatj+5hatk .

Find vecB xx vecA if vecA = 3hati - 2hatj + 6hatk and vecB = hati - hatj + hatk .

Find the scalar product of vectors veca=2hati-hatj+2hatk and vecb=hati-3hatj-5hatk

Find the unit vector in the direction of the sum of the vectors veca=2hati+2hatj-5hatk and vecb=2hati+hatj+3hatk .

Find the unit vector in the direction of the difference of vector (veca-vecb),veca=4hati+5hatj+6hatk and vecb=2hati+3hatj+4hatk .

The projection of the vector vecA = hat - 2hatj + hatk on the vector vecB = 4hati - 4hatj + 7hatk is

Find a vector and unit vector perpendicular to each of the vector veca+vecb and veca-vecb Where veca = 3hati+2hatj+2hatk & vecb = hati+2hatj-2hatk .

If vectors vecA and vecB are 3hati-4hatj+5hatk and 2hati+3hatj-4hatk respectively. then find the unit vector parallel to vecA+vecB

If 4 hati + 7 hat j + 8 hatk, 2 hati +3 hatj + 4 hatk and 2 hati + 5 hatj + 7 hatk are the position vectors of the vertices A, B and C respectively of triangle ABC . The position vector of the point where the bisector of angle A meets BC, is