Coplanarity of points

Proving coplanarity of four points

Coplanar points are the points that are in the same plane.Thus,Can 150 points be coplanar? Can 3 points be non-coplanar?

The number of planes that are equidistant from four non-coplanar points is a.3 b.4 c.7 d.9

A point P moves in such a way that the ratio of its distance from two coplanar points is always a fixed number (!=1). Then,identify the locus of the point.

A, B, C, D and E are coplanar points and three of them lie in a straight line. What is the maximum number of triangles that can be drawn with these points as their vertices ?

The lines (x-1)/(1)=(y-1)/(2)=(z-1)/(3) and (x-4)/(2)=(y-6)/(3)=(z-7)/(3) are coplanar. Their point of intersection is

If A,B,C,D and E are five coplanar points,( then the value of )/(DA)+bar(DB)+bar(DC)+bar(AE)+bar(BE)+bar(CE) is equal to

Show that the coplanar points (-1,-6,10),(1,-3,4),(-5,-1,1) and (-7,-4,7) are the vertices of a rhombus.

If A, B, C, D, E are five coplanar points, then overline(DA)+overline(DB)+overline(DC)+overline(AE)+overline(BE)+overline(CE)=