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Find the angle between the lines whose d...

Find the angle between the lines whose direction cosines are given by the equations `3l + m + 5n = 0` and `6mn - 2nl + 5lm = 0`

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Direction Cosines of the two lines are given by the equations `3l+m+5n=0` and `6mn-2l+5lm=0`
From first equation we get, `m=-5n-3l`
Put it in second equation we get,
`-30n^2-45nl-15l^2=0`
`2n^2+3nl+l^2=0`
`2n^2+2nl+nl+l^2=0`
`(2n+l)(n+l)=0`
If `l=-2n`, then
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