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Shortest distance between two skew lines...

Shortest distance between two skew lines in vector + cartesian form

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Let A( vec a)a n dB( vec b) be points on two skew lines vec r= vec a+lambda vec pa n d vec r= vec b+u vec q and the shortest distance between the skew lines is 1, w h e r e vec pa n d vec q are unit vectors forming adjacent sides of a parallelogram enclosing an area of 1/2 units. If angle betweenA B and the line of shortest distance is 60^0, then A B= a. 1/2 b. 2 c. 1 d. lambda R={10}

Assertion: The shortest distance between the skew lines vecr=veca+alphavecb and vecr=vecc+beta vecd is (|[veca-vecc vecb vecd]|)/(|vecbxxvecd|) , Reason: Two lines are skew lines if they are not coplanar. (A) Both A and R are true and R is the correct explanation of A (B) Both A and R are true R is not te correct explanation of A (C) A is true but R is false. (D) A is false but R is true.

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The shortest distance between the skew lines bar(r) = bar(a_(1)) + lamda bar(b_(1)) "and" bar(r) = bar(a_(2)) + mu bar(b_(2)) is

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