Alternate method for shortest distance calculation for skew lines

Shortest Distance Between Line

Find the shortest distance and the vector equation of the line of shortest distance between the lines given by vecr=3hati+8hatj+3hatk+lamda(3hati-hatj+hatk) and vecr=-3hati-7hatj+6hatk+mu(-3hati+2hatj+4hatk)

Write the formula for the shortest distance between the lines -> r= -> a_1+lambda -> b\ a n d\ -> r= -> a_2+mu -> bdot\

Statement 1: The shortest distance between the lines x/2=y/(-1)=z/2 and (x-1)/(-2)=(y-1)/-2=(z-1)/4 is sqrt(2) . Statement 2: The shortest distance between two parallel lines is the perpendicular distance from any point on one of the lines to the other line.

Assertion: The shortest distance between the skew lines vecr=veca+alphavecb and vecr=vecc+beta vecd is (|[veca-vecc vecb vecd]|)/(|vecbxxvecd|) , Reason: Two lines are skew lines if they are not coplanar. (A) Both A and R are true and R is the correct explanation of A (B) Both A and R are true R is not te correct explanation of A (C) A is true but R is false. (D) A is false but R is true.

Assertion: The shortest distance between the skew lines (x+3)/(-4)=(y-6)/3=z/2 and (x+2)/(-4)=y/1=(z-7)/1 is 9., Reason: Two lines are skew lines if there exists no plane passing through them. (A) Both A and R are true and R is the correct explanation of A (B) Both A and R are true R is not te correct explanation of A (C) A is true but R is false. (D) A is false but R is true.

The shortest distance travelled by a body is called its

Let A( vec a)a n dB( vec b) be points on two skew lines vec r= vec a+lambda vec pa n d vec r= vec b+u vec q and the shortest distance between the skew lines is 1, w h e r e vec pa n d vec q are unit vectors forming adjacent sides of a parallelogram enclosing an area of 1/2 units. If angle betweenA B and the line of shortest distance is 60^0, then A B= a. 1/2 b. 2 c. 1 d. lambda R={10}