Mean of a discrete random variable

Variance of a discrete random variable

The probability distribution of a discrete random variable X is given below The value of k is

The probability distrubtion of a discrete random variable X is as below : Find (P X le 4)

If the probability mass function of a discrete random variable X is P(x)=C/(x^3), x=1,2,3 =0, otherwise Then E(X)=

The probability distribution of a discrete random variable x is given as under Calculate (i) the value of A, if E(X)=2.94. (ii) variance of X.

The pdf of a discrete random variable is defined as f(x)={{:(kx^2","0lexle6),(0", ""elsewhere"):} Then the value of F(4) is

Two probability distributionof the discrete random variable X and Y are given below. Prove that E(Y^(2))=2E(X) .

The probability distribution of discrete random variable X is given below {:(x,2,3,4,5),(P(x),5/K,7/k,9/k,11/k):} find the value of K.

Let 'X' be a discrete random variable. The probability distribution of X is given below : Then E(X) is equal to :