The angle bisectors of a parallelogram form a rectangle.

Show that the bisectors of angles of a parallelogram form a rectangle.

Three statements are given below: I. In a ||gm, the angle bisectors of two adjacent angles enclose a right angle. I. The angle bisectors of a ||gm form a rectangle. III. The triangle formed by joining the midpoints of the sides of an isosceles triangle is not necessarily an isosceles triangle. Which is true?

Prove that the quadrilateral formed by the bisectors of the angles of a parallelogram is a rectangle.

The figure formed by joining the mid-point of the adjacent sides of a parallelogram is a rectangle (b) parallelogram (c) rhombus (d) square

Show that, in a parallelogram ABCD, the internal and external bisectors of angleA and angleB from a rectangle.

If the two diagonals of a parallelogram are equal; it is a rectangle.

The bisector of the angles of a parallelogram enclose a ..................

Complete each of the following statements by means of one of those given in brackets again each: If one pair of opposite sides are equal and parallel, then the figure is ............... (parallelogram, rectangle, trapezium) If in a quadrilateral only one pair of opposite sides are parallel, the quadrilateral is .............. (square, rectangle, trapezium) A line drawn from the mid-point of one side of a triangle .................. another side intersects the third side at its mid-point. (perpendicular to, parallel to, to meet) If one angle of a parallelogram is a right angle, then it is necessarily a .................... (rectangle, square, rhombus) Consecutive angles of parallelogram are ...................... (supplementary, complementary) If both pairs of opposite sides of a quadrilateral are equal, then it is necessarily (rectangle, parallelogram, rhombus) if opposite angles of a quadrilateral are equal, then it is necessarily a ................... (parallelogram, rhombus, rectangle) If consecutive sides of a parallelogram are equal, then it is necessarily a ............. (kite, rhombus, square)