Two chord AB and AC of a circle are equal. Prove that the centre of a circle lies on the angle bisector of `/_BAC`

Two chords AB and AC of a circle are equal. Prove that the centre of the circle lies on the angle bisector of /_BAC.

If two chords AB and AC of a circle with centre O are such that the centre O lies on the bisector of /_BAC, prove that AB=AC, i.e. the chords are equal.

If two chords AB and AB of a circle with centre O are such that the centre O lies on the bisector of /_BAC; Prove that AB=AC

Theorem: 4( iii) If two equal chords are drawn from a point on the circle; then the centre of a circle will lie on angle bisector of these two chords.

In the given figure,AB and AC are two equal chords of a circle with centre O.Show that o lies on the bisectors of /_BAC.

Equal chords of a circle subtend equal angles at the centre.

Prove that equal chords of a circle subtend equal angles at the centre.

Prove that the centre of a circle touching two intersecting lines lies on the angle bisector of the lines.

If the length of a chord of a circle is equal to that of the radius of the circle , then the angle subtended , in radians , at the centre of the circle by the chord is

Let two chords AB and AC of the larger circle having same centre touch the smaller circle having same centre at X and Y. Then XY = ?