If z is purely imaginary ; then `arg(z)=pmpi/2`

If z is purely real; then arg(z)=0 or pi

If the number (z-1)/(z+1) is purely imaginary, then

If the ratio (1-z)/(1+z) is purely imaginary, then

Let A(z_1),B(z_2) and C(z_3) be the vertices of an equilateral triangle in the Argand plane such that |z_1|=|z_2|=|z_3|. Then (A) (z_2+z_3)/(2z_1-z_2-z_3) is purely real (B) (z_2-z_3)/(2z_1-z_2-z_3) is purely imaginary (C) |arg(z_1/z_2)|=2 arg((z_3-z_2)/(z_1-z_2))| (D) none of these

If (3 z_(1))/(5 z_(2)) is purely imaginary, then |(2z_(1)-z_(2))/(2z_(1) + z_(2))| is equal to _________

If (5z_(1))/(7z_(2)) is purely imaginary then |(2z_(1)+3z_(2))/(2z_(1)-3z_(2))|=

If w=(z+4i)/(z+2i) is purely imaginary then find |z+3i|.

If (z-1)/(z-i) is purely imaginary then find the minimum value of abs(z-(3+3i))

If z is purely imaginary and Im (z) lt 0 , then arg(i bar(z)) + arg(z) is equal to