A man standing on a level plane observes the elevation of the top of a pole to be `theta`. He then walks a distance equal to double the height of the pole and then finds that the elevation is now `2theta`. The value of `cottheta` is

A man standing on a level plane observes theanlge of elevation of top of pole to be 'a' He walks a distance equal to double the heightof pole towards it and finds that the elevationis 2a then a=

A man standing on a level plane observes the anlge of elevation of top of pole to be ' alpha '. He walks a distance equal to double the height of pole towards it and finds that the elevation in 2 alpha " then " alpha =

A man standing on a horizontal plane, observes the angle of elevation of the top of a tower to be alpha .After walking a distance equal to double the height of the tower,the angle of elevation becomes 2 alpha then alpha is-

A person standing on the ground observes the angle of elevation of the top of a tower to be 30^@ On walking a distance a in a certain direction, he finds the elevation of the top to be same as before. He then walks a distance 5/3 a at right angles to his former direction, and finds that the elevation of the top has doubled. The height of the tower is

A person standing on the ground observes the angle of elevation of the top of a tower to be 30^@ On walking a distance a in a certain direction, he finds the elevation of the top to be same as before. He then walks a distance 5/3 a at right angles to his former direction, and finds that the elevation of the top has doubled. The height of the tower is

A person observed that the angle of elevation at the top of a pole of height 5 metre is 30^(@) . Then the distance of the person from the pole is :

A person observes that the angle of elevation of the top of a pole of height 15 metre is 30^(@) .What is the distance (in metres) of the person from the pole ?