The reciprocals of the terms of given GP forms a GP

if S is the sum,P the product and R the sum of reciprocals of n terms in G.P. prove that P^(2)R^(n)=S^(n)

In a G.P.the product of the first four terms is 4 and the second term is the reciprocal of the fourth term.The sum of infinite terms of the G.P is

If S be the sum,p the product and R the sum of the reciprocals of n terms of a G.P.,then ((S)/(R))^(n) is equal to

The product of three consecutive terms of a G.P. is 512. If 4 is added to each of the first and the second of these terms, the three terms now form an A.P. Then the sum of the original three terms of the given G.P. is

The product of three consecutive terms of a GP is 512. If 4 is added to each of the first and the second of these terms,the three terms now form an AP.Then the sum of the original three terms of the given GP is: (a) 36 (b) 32 (c) 24 (d) 28

If the product of three terms of a G.P is 729 then find the G.M of the G.P.

If sum of 3 terms of a G.P. is S product is P ,and sum of reciprocal of its terms is R, then P^(2)R^(3) equals to-