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The coordinates of the radical center ca...

The coordinates of the radical center can be found by solving the equation `S_1=S_2=S_3

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Let S_(1) and S_(2) be circle passing through (2,3) and touching the coordinate axis and S be the circle having common points of S_(1) and S_(2) as the centre and radius equal to G.M of radius of S_(1) and S_(2) then

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Let S_(1) and S_(2) be circle passing through (2,3) and touching the coordinate acea and S be the circle having common points of S_(1) and S_(2) as the centre and radius equal to G.M of radius of S_(1) and S_(2) then

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Statement 1 : Let S_1: x^2+y^2-10 x-12 y-39=0, S_2 x^2+y^2-2x-4y+1=0 and S_3:2x^2+2y^2-20 x=24 y+78=0. The radical center of these circles taken pairwise is (-2,-3)dot Statement 2 : The point of intersection of three radical axes of three circles taken in pairs is known as the radical center.

The parabola x^2=4y and y^2=4x divide the square region bounded by the lines x=4 , y=4 and the coordinate axes. If S_1, S_2, S_3 are respectively the areas of these parts numbered from top to bottom, then S_1 : S_2 : S_3 is (A) 2:1:2 (B) 1:2:1 (C) 1:2:3 (D) 1:1:1

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In a G.P. if S_1 , S_2 & S_3 denote respectively the sums of the first n terms , first 2 n terms and first 3 n terms , then prove that, S_(1)^(2)+S_(2)^(2)=S_(1)(S_2+S_3) .