The equation of normal at point whose parameter is t

The equation of tangent at point whose parameter is t

Equation of normal in Point form

The equation of the normal to the curve parametrically represented by x=t^(2)+3t-8 and y=2t^(2)-2t-5 at the point P(2,-1) is

The equation of the normal at the point t = (pi)/4 to the curve x=2sin(t), y=2cos(t) is :

Find the equation of normal at point (a, a) of the curve xy = a^(2) .

Show that the normal at a point (at^2_1, 2at_1) on the parabola y^2 = 4ax cuts the curve again at the point whose parameter t_2 = -t_1 - 2/t_1 .

The Cartesian equation of the curve whose parametric equations are x=t^(2)+2t+3 " and " y=t+1 " is a parabola "(C)" then the equation of the directrix of the curve 'C' is.(where t is a parameter)

The Cartesian equation of the curve whose parametric equations are x=t^(2) +2t+3 and y=t+1 is a parabola (C) then the equation of the directrix of the curve 'C' is.(where t is a parameter)

The normal at a point with parameter 2 on y^(2)=6x again meets the parabola at point

The equation of normal to the curve y=x^(2)+4x at the point whose ordinate is -3, is