For any two events A and B ; Prove that exactly one of the A; B occurs is given by `P(A)+P(B)-2P(AuuB)=P(AuuB)-P(AnnB)`

For any two evens A and B P(AuuB) =

For any two events A and B prove that P(A uu B)<=P(A)+P(B)

The probability of simultaneous occurrence of at least one of two events A and B is p.If the probability that exactly one of A,B occurs is q then prove that P(bar(A))+P(bar(B))=2-2p+q

Let for two events A and B , P(A)=p and P(B)=q . Statement-1 : The probability that exactly one of the event A and B occurs is p+q-2pq Statement-2 : P(AcupB)=P(A)+P(B)-P(AcapB) .

Aa n dB are two independent events. C is event in which exactly one of AorB occurs. Prove that P(C)geqP(AuuB)P(AnnB)dot

Let A and B are two events such that P(exactly one) = 2/5 , P(A uu B)= 1/2 then P(A nn B)=

If A and B are two events, then P( A nnB)= P( A )P( B ) b. 1-P(A)-P(B) c. P(A)+P(B)-P(AuuB) d. P(B)-P(AnnB)