If f is a bijection and g is the inverse of f; then `fog = I_B` and `gof = I_A` where `I_A` and `I_B` are the identity functions on the sets A and B respectively.

If f : A to B is bijection and g : B to A is that inverse of f , then fog is equal to

Let f:A rarr B, and let I_(A) and I_(B) be identity functions on A and B respectively.Prove that (foI_(A))=f and (I_(B)Of)=f

If f:A rarr B and g:B rarr C are onto functions show that gof is an onto function.

If f: A-> B and g: B-> C be the bijective function, then (gof)^(-1) is:

Two solid spheres A and B each of radius R are made of materials of densities rho_A and rho_B respectively. Their moments of inertia about a diameter are I_A and I_B respectively. The value of I_A/I_B is

Suppose l+A is non-singular.Let B=(I+A)^(-1) and C=I-A, then .... (where I,A,O are identity square and null matrices of order n respectively)

Two rotating bodies A and B of masses m and 2m with moments of inertia I_A and I_B (I_B gt I_A) have equal kinetic energy of rotation. If L_A and L_b be their angular momenta respectively, then

If f:A rarr B and g:B rarr C are one-one functions,show that gof is one-one function.