[" to "x:],[qquad 1.(i)e^(x)((x-1)/(x^(2)))]

I=int(e^(2x)-1)/(e^(2x))dx

f(x)=(e^(2x)-1)/(e^(2x)+1) is

f(x)=((e^(2x)-1)/(e^(2x)+1)) is

Evaluate: (i) int e^(x)((1)/(x)-(1)/(x^(2)))dx (ii) int e^(x)(sin x+cos x)dx

f(x) = ((e^(2x)-1)/(e^(2x)+1)) is

Find (i) int e^(x)(tan^(-1)x+(1)/(1+x^(2)))dxint((x^(2)+1)e^(x))/((1+x)^(2)))dx

If I=lim_(x to 0) sin((e^(x)-x-1-(x^(2))/(2))/(x^(2))) , then limit

" (i) "int(e^(tan^(-1)x)dx)/((1+x^(2))

int e^(x)((x-2)/((x-1)^(2)))dx is equal to (i) (e^(x))/(x-1)+C (ii) (e^(x))/((x-1)^(2))+C( iii) (2e^(x))/((x-1)^(2))+C( iv )(e^(x)-1)/(x-1)+C