Solve: `2^(x+2) xx 27^(x/(x-1))=9`

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Solve 2^(x+2)27^(x/(x-1))=9

What are the roots of the equation 2^(x+2).27^(x/(x-1)) = 9 ?

Solve: "4.3^(x+1)=27+9^(x)

The roots os the equation 2^(x+2)27(x)/(x-1)=9 are given by

Solve ((2x+1)!)/((x+2)!)xx((x-1)!)/((2x-1)!)=(3)/(5)(x in N)

Solve :8xx2^(2x)+4xx2^(x+1)=1+2^(x)

Solve: (1)/((x+3))+(1)/((2x-1))=(11)/((7x+9)),xne-3,(1)/(2),(-9)/(7).