Evaluate: `root(3)72.3; if `log 0.723 = `bar(1).8591`

Evaluate (72.3)^((1)/(3)) if log0.723=1.8591

Evaluate : 2.bar(7)+1.bar(3)

Evaluate : 1.bar(45)+0.bar(3)

Evaluate: root(3)(288root(3)(72root(3)(27)))

Evaluate 3.bar(2)-0.bar(16)

Evaluate : root3(27)+root3(0.008)+root3(0.064)

root3(72.9/0.4096) is equal to :

If log(0.57)=bar(1.756), then the value of log57+log(0.57)^(3)+log backslash sqrt(0.57) is a.0.902 b.1.902 c.bar(2.146)d.bar(1.146)

Evaluate the following limit: (lim)_(x rarr0)(log(1+x))/(3^(x)-1)